LeetCode 147: Insertion Sort List Solution
Master LeetCode problem 147 (Insertion Sort List), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
147. Insertion Sort List
Problem Explanation
Explanation:
-
Algorithmic Idea:
- We start with an empty sorted list and iterate through the input list.
- For each element in the input list, we remove it and insert it in the correct position in the sorted list.
- To insert an element into the sorted list, we compare it with each element from the beginning of the sorted list and find the correct position to insert it.
-
Step-by-Step Iterations:
- For input list [4,2,1,3]:
- Start with an empty sorted list.
- Insert 4 into the sorted list: [4]
- Insert 2 into the sorted list: [2,4]
- Insert 1 into the sorted list: [1,2,4]
- Insert 3 into the sorted list: [1,2,3,4]
- For input list [4,2,1,3]:
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Time Complexity: O(n^2) where n is the number of nodes in the linked list.
-
Space Complexity: O(1)
:
Solution Code
class Solution {
public ListNode insertionSortList(ListNode head) {
if (head == null || head.next == null) {
return head;
}
ListNode dummy = new ListNode(-1);
ListNode curr = head;
while (curr != null) {
ListNode prev = dummy;
ListNode nextNode = curr.next;
while (prev.next != null && prev.next.val < curr.val) {
prev = prev.next;
}
curr.next = prev.next;
prev.next = curr;
curr = nextNode;
}
return dummy.next;
}
}Try It Yourself
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