LeetCode 1486: XOR Operation in an Array Solution

Master LeetCode problem 1486 (XOR Operation in an Array), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1486. XOR Operation in an Array

Easy

Math Bit Manipulation

Problem Explanation

Explanation

To solve this problem, we can create an array nums by generating each element using the formula start + 2*i, where i ranges from 0 to n-1. Then we can calculate the bitwise XOR of all elements in the array nums to get the final result.

Initialize a variable result to 0.
Iterate from 0 to n-1, calculate each element using the formula start + 2*i, and XOR it with the current result.
Return the final result.

Time Complexity

The time complexity of this solution is O(n) where n is the given integer.

Space Complexity

The space complexity of this solution is O(1) as we are not using any extra space that grows with the input size.

Solution Code

class Solution {
    public int xorOperation(int n, int start) {
        int result = 0;
        for (int i = 0; i < n; i++) {
            result ^= start + 2*i;
        }
        return result;
    }
}

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What is the time complexity of LeetCode 1486 (XOR Operation in an Array)?

The time complexity for LeetCode 1486 (XOR Operation in an Array) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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