LeetCode 1510: Stone Game IV Solution

Problem Explanation

Explanation:

This problem can be solved using dynamic programming.
We will create a dp array to store the result of each number of stones from 1 to n.
We iterate through the numbers from 1 to n and calculate if Alice can win the game by removing a square number of stones.
If Alice can make a move such that the remaining stones would lead Bob to lose the game, then Alice wins.
We return the result for n = 1 as true because Alice starts the game.

Time Complexity: O(n√n) Space Complexity: O(n)

Solution Code

class Solution {
    public boolean winnerSquareGame(int n) {
        boolean[] dp = new boolean[n + 1];
        dp[0] = false;

        for (int i = 1; i <= n; i++) {
            for (int j = 1; j * j <= i; j++) {
                if (!dp[i - j * j]) {
                    dp[i] = true;
                    break;
                }
            }
        }

        return dp[n];
    }
}

Frequently Asked Questions

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The time complexity for LeetCode 1510 (Stone Game IV) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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1510. Stone Game IV