LeetCode 1518: Water Bottles Solution

Problem Explanation

Explanation:

To solve this problem, we need to simulate the process of exchanging empty water bottles for full ones until no more exchanges can be made. We keep track of the total number of water bottles we have consumed during this process.

Initialize a variable total to store the total number of water bottles consumed.
While the number of bottles we have is greater than or equal to the number of bottles required for an exchange:
- Calculate how many bottles we can exchange and update the total accordingly.
- Update the number of bottles we have left after the exchange.
Return the total number of water bottles consumed.

The time complexity of this solution is O(log(numBottles)), and the space complexity is O(1).

Solution Code

class Solution {
    public int numWaterBottles(int numBottles, int numExchange) {
        int total = numBottles;
        while (numBottles >= numExchange) {
            total += numBottles / numExchange;
            numBottles = numBottles / numExchange + numBottles % numExchange;
        }
        return total;
    }
}

Frequently Asked Questions

How to solve LeetCode 1518 (Water Bottles)?

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What is the time complexity of LeetCode 1518 (Water Bottles)?

The time complexity for LeetCode 1518 (Water Bottles) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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1518. Water Bottles