LeetCode 1523: Count Odd Numbers in an Interval Range Solution

Master LeetCode problem 1523 (Count Odd Numbers in an Interval Range), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1523. Count Odd Numbers in an Interval Range

Easy

Math

Problem Explanation

Explanation:

To count the number of odd numbers between a given range [low, high], we can simply calculate the count of odd numbers in the entire range [0, high] and subtract the count of odd numbers in the range [0, low-1]. This gives us the count of odd numbers in the range [low, high].

Algorithm:

Calculate the count of odd numbers in the range [0, high] using the formula (high + 1) / 2.
Calculate the count of odd numbers in the range [0, low-1] using the formula low / 2.
Return the difference of the counts calculated in steps 1 and 2.

Time Complexity:

The time complexity of this algorithm is O(1) as it requires only simple arithmetic operations.

Space Complexity:

The space complexity of this algorithm is O(1) as it uses a constant amount of extra space.

Solution Code

class Solution {
    public int countOdds(int low, int high) {
        return (high + 1) / 2 - low / 2;
    }
}

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