LeetCode 1533: Find the Index of the Large Integer Solution

Master LeetCode problem 1533 (Find the Index of the Large Integer), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1533. Find the Index of the Large Integer

Problem Explanation

Explanation

To solve this problem, we need to find the index of the largest integer in a given array. We can achieve this by iterating through the array and keeping track of the largest value seen so far along with its corresponding index. By comparing each element with the current maximum value, we can update the maximum value and its index accordingly.

Algorithmic Steps:

  1. Initialize variables maxValue to store the maximum value and maxIndex to store its corresponding index.
  2. Iterate through the array and for each element:
    • Compare the element with maxValue.
    • If the element is greater than maxValue, update maxValue and maxIndex.
  3. Return the maxIndex as the index of the largest integer.

Time Complexity

The time complexity of this solution is O(n) where n is the number of elements in the input array.

Space Complexity

The space complexity of this solution is O(1) as we are using a constant amount of extra space regardless of the input size.

Solution Code

class Solution {
    public int findMaxIndex(int[] arr) {
        int maxValue = Integer.MIN_VALUE;
        int maxIndex = -1;
        
        for (int i = 0; i < arr.length; i++) {
            if (arr[i] > maxValue) {
                maxValue = arr[i];
                maxIndex = i;
            }
        }
        
        return maxIndex;
    }
}

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What is the time complexity of LeetCode 1533 (Find the Index of the Large Integer)?

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