LeetCode 1535: Find the Winner of an Array Game Solution

Master LeetCode problem 1535 (Find the Winner of an Array Game), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1535. Find the Winner of an Array Game

Medium

Array Simulation

Problem Explanation

Explanation

To solve this problem, we can simulate the game rounds by iterating over the array and keeping track of the current winner and their win count. We will update the winner and win count after each round based on the comparison of the first two elements of the array. Once a winner has won k consecutive rounds, we return the winner.

Algorithm

Initialize variables winner and winCount to keep track of the current winner and their win count.
Iterate over the array starting from index 1.
Compare the first two elements of the array.
If the current element is greater than the winner, update the winner and reset the win count to 1.
If the current element is equal to the winner, increment the win count.
If the win count reaches k, return the winner.

Time Complexity

The time complexity of this algorithm is O(n) where n is the number of elements in the array.

Space Complexity

The space complexity is O(1) as we are using only a constant amount of extra space.

Solution Code

class Solution {
    public int getWinner(int[] arr, int k) {
        int winner = arr[0];
        int winCount = 0;
        
        for (int i = 1; i < arr.length; i++) {
            if (arr[i] > winner) {
                winner = arr[i];
                winCount = 1;
            } else {
                winCount++;
            }
            
            if (winCount == k) {
                return winner;
            }
        }
        
        return winner;
    }
}

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