LeetCode 1557: Minimum Number of Vertices to Reach All Nodes Solution
Master LeetCode problem 1557 (Minimum Number of Vertices to Reach All Nodes), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1557. Minimum Number of Vertices to Reach All Nodes
Problem Explanation
Explanation
To find the minimum number of vertices to reach all nodes in a directed acyclic graph, we can identify the vertices that have no incoming edges. These vertices are guaranteed to be able to reach all other vertices in the graph. Therefore, we can simply iterate through all the edges and mark the destination vertices. Finally, we return the vertices that were not marked.
Algorithm
- Initialize a set to store all vertices.
- Iterate through all edges and mark the destination vertices.
- Iterate through all vertices and add the ones that were not marked to the result set.
- Return the result set as the answer.
Time Complexity
The time complexity of this algorithm is O(n + E), where n is the number of vertices and E is the number of edges.
Space Complexity
The space complexity of this algorithm is O(n), where n is the number of vertices.
Solution Code
import java.util.*;
class Solution {
public List<Integer> findSmallestSetOfVertices(int n, List<List<Integer>> edges) {
Set<Integer> reachable = new HashSet<>();
for (List<Integer> edge : edges) {
reachable.add(edge.get(1));
}
List<Integer> result = new ArrayList<>();
for (int i = 0; i < n; i++) {
if (!reachable.contains(i)) {
result.add(i);
}
}
return result;
}
}Try It Yourself
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