LeetCode 1607: Sellers With No Sales Solution

Master LeetCode problem 1607 (Sellers With No Sales), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1607. Sellers With No Sales

Easy

Database

Problem Explanation

Explanation

Given a list of sellers and their corresponding sales, we need to find the sellers who have not made any sales. We can achieve this by iterating through the list of sales and keeping track of the sellers who have made at least one sale. Then, we can iterate through the list of all sellers and identify the ones who have not made any sales.

Algorithmic Idea

Create a set to store sellers who have made at least one sale.
Iterate through the list of sales and add the seller to the set.
Iterate through the list of all sellers and check if the seller is not in the set of sellers who have made sales.

Time Complexity

The time complexity of this algorithm is O(n), where n is the total number of sellers.

Space Complexity

The space complexity of this algorithm is O(n), where n is the total number of sellers.

Solution Code

import java.util.*;

class Solution {
    public List<Integer> findSellersWithNoSales(List<Integer> sales, List<Integer> allSellers) {
        Set<Integer> sellersWithSales = new HashSet<>();
        
        for (int sale : sales) {
            sellersWithSales.add(sale);
        }
        
        List<Integer> sellersWithNoSales = new ArrayList<>();
        
        for (int seller : allSellers) {
            if (!sellersWithSales.contains(seller)) {
                sellersWithNoSales.add(seller);
            }
        }
        
        return sellersWithNoSales;
    }
}

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The time complexity for LeetCode 1607 (Sellers With No Sales) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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