LeetCode 1630: Arithmetic Subarrays Solution

Master LeetCode problem 1630 (Arithmetic Subarrays), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1630. Arithmetic Subarrays

Problem Explanation

Explanation

To solve this problem, we need to iterate through each range query and check if the subarray within that range can be rearranged to form an arithmetic sequence. We can do this by first sorting the subarray and then checking if the sorted subarray is an arithmetic sequence. To check if a sorted subarray is an arithmetic sequence, we need to verify that the difference between each pair of consecutive elements is the same.

  • Time complexity: O(mnlog(n)) where m is the number of queries and n is the length of the input array.
  • Space complexity: O(n) for storing the sorted subarray.

Solution Code

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

class Solution {
    public List<Boolean> checkArithmeticSubarrays(int[] nums, int[] l, int[] r) {
        List<Boolean> result = new ArrayList<>();
        
        for(int i = 0; i < l.length; i++) {
            int start = l[i];
            int end = r[i];
            
            int[] subArray = Arrays.copyOfRange(nums, start, end+1);
            Arrays.sort(subArray);
            
            boolean isArithmetic = true;
            int diff = subArray[1] - subArray[0];
            for(int j = 2; j < subArray.length; j++) {
                if(subArray[j] - subArray[j-1] != diff) {
                    isArithmetic = false;
                    break;
                }
            }
            
            result.add(isArithmetic);
        }
        
        return result;
    }
}

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