LeetCode 1656: Design an Ordered Stream Solution
Master LeetCode problem 1656 (Design an Ordered Stream), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1656. Design an Ordered Stream
Problem Explanation
Explanation:
- We can use an array to store the values inserted in the stream.
- We keep track of the last inserted id so that when a new pair is inserted, we can identify the largest chunk of currently inserted values that appear next in the order.
- We return this chunk after each insertion.
Algorithm:
- Initialize an array
streamof sizento store the values. - Initialize a variable
ptrto keep track of the last inserted id. - In the
insertfunction: a. Update the value at indexidKey - 1instream. b. Check fromptrtonin thestreamarray to find the largest chunk of values that can be returned. c. UpdateptrtoidKeyif the value at indexptris not null. d. Return the chunk of values found.
Time Complexity: O(n) for each insert operation where n is the size of the stream.
Space Complexity: O(n) to store the stream of values.
:
Solution Code
class OrderedStream {
String[] stream;
int ptr;
public OrderedStream(int n) {
stream = new String[n];
ptr = 0;
}
public List<String> insert(int idKey, String value) {
List<String> result = new ArrayList<>();
stream[idKey - 1] = value;
while (ptr < stream.length && stream[ptr] != null) {
result.add(stream[ptr]);
ptr++;
}
return result;
}
}Try It Yourself
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