LeetCode 1665: Minimum Initial Energy to Finish Tasks Solution

Master LeetCode problem 1665 (Minimum Initial Energy to Finish Tasks), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1665. Minimum Initial Energy to Finish Tasks

Hard

Array Greedy Sorting

Problem Explanation

Explanation

To solve this problem, we can sort the tasks in descending order of the difference between actual energy and minimum energy required. Then, we iterate through the tasks and calculate the total initial energy needed to finish all tasks. We keep track of the current energy as we process each task.

Sort the tasks in descending order based on the difference between actual and minimum energy required.
Initialize a variable initialEnergy to 0.
Initialize a variable currentEnergy to 0.
Iterate through the sorted tasks.
For each task, if the current energy is less than the minimum energy required for the task, update the initial energy needed and set the current energy to the minimum energy required for the task.
Return the total initial energy needed.

Time Complexity: O(n log n) where n is the number of tasks Space Complexity: O(1)

Solution Code

import java.util.Arrays;

class Solution {
    public int minimumEffort(int[][] tasks) {
        Arrays.sort(tasks, (a, b) -> (b[1] - b[0]) - (a[1] - a[0]));
        int initialEnergy = 0;
        int currentEnergy = 0;
        
        for (int[] task : tasks) {
            if (currentEnergy < task[1]) {
                initialEnergy += task[1] - currentEnergy;
                currentEnergy = task[1];
            }
            currentEnergy -= task[0];
        }
        
        return initialEnergy;
    }
}

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