LeetCode 1668: Maximum Repeating Substring Solution
Master LeetCode problem 1668 (Maximum Repeating Substring), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1668. Maximum Repeating Substring
Problem Explanation
Explanation:
To solve this problem, we can iterate through the sequence and for each character, check if the word is a substring starting from that character. We can keep track of the maximum repeating value of the word in the sequence.
- Start with a counter initialized to 0.
- Iterate through the sequence.
- For each character, check if the word is a substring starting from that character.
- If it is a substring, increment the counter.
- Keep track of the maximum counter value encountered.
- Return the maximum counter value as the result.
Time Complexity:
The time complexity of this approach is O(n*m) where n is the length of the sequence and m is the length of the word.
Space Complexity:
The space complexity is O(1) as we are using only a constant amount of extra space.
:
Solution Code
class Solution {
public int maxRepeating(String sequence, String word) {
int maxRepeating = 0;
for (int i = 0; i <= sequence.length() - word.length(); i++) {
int k = 0;
while (i + k + word.length() <= sequence.length() && sequence.substring(i + k, i + k + word.length()).equals(word)) {
k++;
}
maxRepeating = Math.max(maxRepeating, k);
}
return maxRepeating;
}
}Try It Yourself
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