LeetCode 1673: Find the Most Competitive Subsequence Solution

Master LeetCode problem 1673 (Find the Most Competitive Subsequence), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1673. Find the Most Competitive Subsequence

Problem Explanation

Explanation

To solve this problem, we can use a monotonic stack to keep track of the most competitive subsequence. We iterate over the input array nums and for each element, we check if adding it to the stack would make the stack size exceed k or if the current element is smaller than the top of the stack and we can still make a subsequence of length k. In such cases, we pop elements from the stack until the conditions are satisfied, and then push the current element onto the stack.

By the end of the iteration, the stack will contain the most competitive subsequence of size k.

Time Complexity: O(n) where n is the number of elements in the input array nums. Space Complexity: O(n) where n is the number of elements in the input array nums.

Solution Code

public int[] mostCompetitive(int[] nums, int k) {
    int n = nums.length;
    int[] stack = new int[k];
    int top = -1;
    
    for (int i = 0; i < n; i++) {
        while (top >= 0 && nums[i] < stack[top] && k - top < n - i) {
            top--;
        }
        if (top < k - 1) {
            stack[++top] = nums[i];
        }
    }
    
    return stack;
}

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