LeetCode 1709: Biggest Window Between Visits Solution
Master LeetCode problem 1709 (Biggest Window Between Visits), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1709. Biggest Window Between Visits
Problem Explanation
Explanation
To solve this problem, we can iterate through the given array and keep track of the maximum distance between the same elements encountered so far. We can achieve this by using a HashMap to store the index of each element as we iterate through the array. When we encounter a repeated element, we calculate the distance between the current index and the previously stored index for that element and update the maximum distance if needed.
- Start with an empty HashMap to store elements and their index.
- Initialize a variable
maxDistanceto 0 to keep track of the maximum distance between same elements. - Iterate through the array.
- If the element is already present in the HashMap, calculate the distance between the current index and the previously stored index for that element.
- Update
maxDistanceif the calculated distance is greater. - Update the index of the element in the HashMap.
- Return the
maxDistanceas the result.
Time Complexity: O(n) where n is the number of elements in the array. Space Complexity: O(n) for the HashMap to store elements and their index.
Solution Code
class Solution {
public int maxDistance(int[] nums) {
Map<Integer, Integer> indexMap = new HashMap<>();
int maxDistance = 0;
for (int i = 0; i < nums.length; i++) {
if (indexMap.containsKey(nums[i])) {
maxDistance = Math.max(maxDistance, i - indexMap.get(nums[i]));
}
indexMap.put(nums[i], i);
}
return maxDistance;
}
}Try It Yourself
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