LeetCode 1747: Leetflex Banned Accounts Solution

Master LeetCode problem 1747 (Leetflex Banned Accounts), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1747. Leetflex Banned Accounts

Medium

Database

Problem Explanation

Explanation:

To solve this problem, we can simulate the process of banning accounts and counting the number of users who have been banned. We can use a hash set to keep track of banned accounts and their associated users. By iterating through the given account and user arrays, we can check if the account is banned. If the account is not banned, we add it to the hash set and increment the count of banned users. If the account is already banned, we skip it and move on to the next account.

Algorithmic Idea:

Initialize a hash set to store banned accounts.
Initialize a variable to keep track of the count of banned users.
Iterate through the given arrays of accounts and users.
Check if the current account is already in the hash set. If not, add it to the hash set and increment the count of banned users.
Return the count of banned users.

Time Complexity:

The time complexity of this solution is O(n), where n is the number of accounts/users provided.

Space Complexity:

The space complexity of this solution is O(n), where n is the number of accounts/users provided.

Solution Code

public int countBannedUsers(int[] accounts, int[] users) {
    Set<Integer> bannedAccounts = new HashSet<>();
    int bannedUsersCount = 0;
    
    for (int i = 0; i < accounts.length; i++) {
        if (!bannedAccounts.contains(accounts[i])) {
            bannedAccounts.add(accounts[i]);
            bannedUsersCount++;
        }
    }
    
    return bannedUsersCount;
}

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