LeetCode 1805: Number of Different Integers in a String
LeetCode 1805 Solution Explanation
Explanation:
To solve this problem, we will iterate over the input string and replace non-digit characters with spaces. Then, we will split the string based on spaces and add the distinct integers to a set. Finally, we return the size of the set as the number of different integers in the string.
- Time Complexity: O(n) where n is the length of the input string.
- Space Complexity: O(n) for the set to store distinct integers.
LeetCode 1805 Solutions in Java, C++, Python
import java.util.HashSet;
import java.util.Set;
class Solution {
public int numDifferentIntegers(String word) {
Set<String> set = new HashSet<>();
word = word.replaceAll("[^0-9]", " ");
for (String num : word.split("\\s+")) {
if (!num.equals("")) {
set.add(num.replaceFirst("^0+(?!$)", ""));
}
}
return set.size();
}
}Interactive Code Editor for LeetCode 1805
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