LeetCode 1822: Sign of the Product of an Array Solution

Master LeetCode problem 1822 (Sign of the Product of an Array), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1822. Sign of the Product of an Array

Easy

Array Math

Problem Explanation

Explanation:

To solve this problem, we need to calculate the product of all elements in the given array nums. Then, we can determine the sign of the product based on the rules provided in the problem description.

Initialize a variable product to store the product of all elements in the array.
Iterate through each element in the array and update the product.
Determine the sign of the product using the signFunc function.
Return the sign of the product.

Time Complexity:

The time complexity of this solution is O(N), where N is the number of elements in the input array nums.

Space Complexity:

The space complexity of this solution is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int arraySign(int[] nums) {
        int product = 1;
        for (int num : nums) {
            product *= num;
        }
        
        return signFunc(product);
    }
    
    private int signFunc(int x) {
        if (x > 0) {
            return 1;
        } else if (x < 0) {
            return -1;
        } else {
            return 0;
        }
    }
}

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Frequently Asked Questions

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What is the time complexity of LeetCode 1822 (Sign of the Product of an Array)?

The time complexity for LeetCode 1822 (Sign of the Product of an Array) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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