LeetCode 1836: Remove Duplicates From an Unsorted Linked List Solution
Master LeetCode problem 1836 (Remove Duplicates From an Unsorted Linked List), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1836. Remove Duplicates From an Unsorted Linked List
Problem Explanation
Explanation:
To remove duplicates from an unsorted linked list, we can use a hash set to keep track of unique values encountered so far. We iterate through the linked list, adding each value to the hash set. If a value is already in the hash set, we remove it from the linked list. This way, we ensure that only unique values remain in the linked list.
Algorithm:
- Initialize a hash set to store unique values.
- Initialize two pointers,
prevandcurrent, to traverse the linked list. - Traverse the linked list:
- If the current value is not in the hash set, add it to the set and move both pointers to the next node.
- If the current value is in the hash set, remove the current node by updating
prev's next pointer.
- Return the modified linked list.
Time Complexity: O(N) where N is the number of nodes in the linked list. Space Complexity: O(N) for the hash set to store unique values.
:
Solution Code
public ListNode removeDuplicates(ListNode head) {
Set<Integer> set = new HashSet<>();
ListNode dummy = new ListNode(0);
dummy.next = head;
ListNode prev = dummy;
ListNode current = head;
while (current != null) {
if (!set.contains(current.val)) {
set.add(current.val);
prev = current;
} else {
prev.next = current.next;
}
current = current.next;
}
return dummy.next;
}Try It Yourself
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