LeetCode 1837: Sum of Digits in Base K Solution

Master LeetCode problem 1837 (Sum of Digits in Base K), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1837. Sum of Digits in Base K

Easy

Math

Problem Explanation

Explanation

To solve this problem, we can convert the given number n from base 10 to base k. Then, we sum the digits of the converted number to get the final result. We can achieve this by repeatedly dividing the number by k to get the remainder which will be the least significant digit in base k. We keep track of the sum of digits as we go along.

Algorithm:

Initialize a variable sum to 0.
While n is greater than 0:
- Calculate the remainder by taking n % k.
- Add the remainder to sum.
- Update n by doing integer division n / k.
Return the sum.

Time Complexity

The time complexity of this algorithm is O(logk(n)) where n is the input number and k is the base.

Space Complexity

The space complexity of this algorithm is O(1) as we are using a constant amount of extra space.

Solution Code

class Solution {
    public int sumBase(int n, int k) {
        int sum = 0;
        while (n > 0) {
            sum += n % k;
            n /= k;
        }
        return sum;
    }
}

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What is the time complexity of LeetCode 1837 (Sum of Digits in Base K)?

The time complexity for LeetCode 1837 (Sum of Digits in Base K) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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