LeetCode 1846: Maximum Element After Decreasing and Rearranging Solution

Master LeetCode problem 1846 (Maximum Element After Decreasing and Rearranging), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1846. Maximum Element After Decreasing and Rearranging

Medium

Array Greedy Sorting

Problem Explanation

Explanation

To find the maximum possible value of an element in the array after performing the operations to satisfy the conditions, we can follow these steps:

Sort the array in non-decreasing order.
Iterate through the sorted array and ensure that each element is not more than one larger than the previous element.
Update any elements that violate this condition by decreasing them to the maximum valid value.

This approach guarantees that the array satisfies the conditions, and the maximum element will be as large as possible.

Time complexity: O(n log n) where n is the length of the input array due to sorting. Space complexity: O(1) as we are not using any extra space other than a few variables.

Solution Code

class Solution {
    public int maximumElementAfterDecrementingAndRearranging(int[] arr) {
        Arrays.sort(arr);
        arr[0] = 1;
        for (int i = 1; i < arr.length; i++) {
            if (arr[i] - arr[i - 1] > 1) {
                arr[i] = arr[i - 1] + 1;
            }
        }
        return arr[arr.length - 1];
    }
}

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