LeetCode 1866: Number of Ways to Rearrange Sticks With K Sticks Visible Solution
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1866. Number of Ways to Rearrange Sticks With K Sticks Visible
Problem Explanation
Explanation:
To solve this problem, we can use dynamic programming. Let's define a 2D array dp[n+1][k+1] where dp[i][j] represents the number of ways to rearrange i sticks such that j sticks are visible from the left.
The recurrence relation can be defined as follows:
- If we place the longest stick first, there will be
dp[i-1][j-1]ways to arrange the remaining sticks with one less stick visible. - If we place any stick other than the longest one first, there will be
dp[i-1][j]ways to arrange the remaining sticks with the same number of sticks visible.
Therefore, dp[i][j] = dp[i-1][j-1] + (i-1) * dp[i-1][j].
The base cases are:
dp[i][0] = 0for alli(no visible sticks)dp[0][j] = 0for allj(no sticks to arrange)dp[1][1] = 1(only one stick, one visible stick)
The final answer will be dp[n][k], modulo 10^9 + 7.
Time complexity: O(nk) Space complexity: O(nk)
:
Solution Code
class Solution {
public int rearrangeSticks(int n, int k) {
int MOD = 1000000007;
long[][] dp = new long[n + 1][k + 1];
dp[0][0] = 1;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= Math.min(i, k); j++) {
dp[i][j] = (dp[i-1][j-1] + (i-1) * dp[i-1][j]) % MOD;
}
}
return (int) dp[n][k];
}
}Try It Yourself
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