LeetCode 1867: Orders With Maximum Quantity Above Average Solution
Master LeetCode problem 1867 (Orders With Maximum Quantity Above Average), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1867. Orders With Maximum Quantity Above Average
Problem Explanation
Explanation
Given a list of orders consisting of items and quantities, we need to find the orders with the maximum quantity above the average quantity of all orders.
Algorithm:
- Calculate the total quantity of all orders and the average quantity.
- Iterate through the orders and keep track of orders with quantities above the average.
- Find the maximum quantity among orders above average.
Time Complexity: O(n) Space Complexity: O(1)
Solution Code
class Solution {
public int maxAboveAverage(int[][] orders) {
int totalQuantity = 0;
for (int[] order : orders) {
totalQuantity += order[1];
}
double average = totalQuantity / orders.length;
int maxAboveAverage = 0;
for (int[] order : orders) {
if (order[1] > average) {
maxAboveAverage = Math.max(maxAboveAverage, order[1]);
}
}
return maxAboveAverage;
}
}Try It Yourself
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