LeetCode 1867: Orders With Maximum Quantity Above Average Solution

Master LeetCode problem 1867 (Orders With Maximum Quantity Above Average), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1867. Orders With Maximum Quantity Above Average

Medium

Problem Explanation

Explanation

Given a list of orders consisting of items and quantities, we need to find the orders with the maximum quantity above the average quantity of all orders.

Algorithm:

  1. Calculate the total quantity of all orders and the average quantity.
  2. Iterate through the orders and keep track of orders with quantities above the average.
  3. Find the maximum quantity among orders above average.

Time Complexity: O(n) Space Complexity: O(1)

Solution Code

class Solution {
    public int maxAboveAverage(int[][] orders) {
        int totalQuantity = 0;
        
        for (int[] order : orders) {
            totalQuantity += order[1];
        }
        
        double average = totalQuantity / orders.length;
        int maxAboveAverage = 0;
        
        for (int[] order : orders) {
            if (order[1] > average) {
                maxAboveAverage = Math.max(maxAboveAverage, order[1]);
            }
        }
        
        return maxAboveAverage;
    }
}

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