LeetCode 1913: Maximum Product Difference Between Two Pairs Solution

Master LeetCode problem 1913 (Maximum Product Difference Between Two Pairs), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1913. Maximum Product Difference Between Two Pairs

Problem Explanation

Explanation

To maximize the product difference between two pairs, we need to select two pairs of numbers that have the largest difference in their products. We can achieve this by sorting the input array. By sorting the array in ascending order, we ensure that the largest numbers are at the end and the smallest numbers are at the beginning. Then, we can calculate the product difference by taking the product of the last two numbers and the product of the first two numbers.

Algorithm

  1. Sort the input array nums in ascending order.
  2. Calculate the product difference by taking the product of the last two numbers and the product of the first two numbers.
  3. Return the maximum product difference calculated.

Time Complexity

The time complexity of this algorithm is O(n log n) due to the sorting step.

Space Complexity

The space complexity of this algorithm is O(1) as we are not using any extra space other than a few variables.

Solution Code

import java.util.Arrays;

class Solution {
    public int maxProductDifference(int[] nums) {
        Arrays.sort(nums);
        int n = nums.length;
        return (nums[n - 1] * nums[n - 2]) - (nums[0] * nums[1]);
    }
}

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