LeetCode 1925: Count Square Sum Triples Solution
Master LeetCode problem 1925 (Count Square Sum Triples), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1925. Count Square Sum Triples
Problem Explanation
Explanation:
To solve this problem, we can iterate through all possible combinations of (a, b, c) such that 1 <= a, b, c <= n, and check if a^2 + b^2 = c^2. We can use three nested loops to iterate through all possible values of a, b, and c. For each combination, we check if the condition a^2 + b^2 = c^2 is satisfied, and if so, we increment a counter to keep track of the number of square triples.
Time Complexity:
The time complexity of this approach is O(n^3) as we are iterating through all possible combinations of a, b, and c.
Space Complexity:
The space complexity of this approach is O(1) as we are not using any extra space apart from a few variables.
:
Solution Code
class Solution {
public int countTriples(int n) {
int count = 0;
for (int a = 1; a <= n; a++) {
for (int b = 1; b <= n; b++) {
for (int c = 1; c <= n; c++) {
if (a * a + b * b == c * c) {
count++;
}
}
}
}
return count;
}
}Try It Yourself
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