LeetCode 1929: Concatenation of Array Solution

Problem Explanation

Explanation:

To solve this problem, we need to create a new array ans by concatenating the input array nums with itself. We can achieve this by iterating over the elements of nums and appending each element to ans twice.

Initialize an empty array ans.
Iterate over the elements of nums and append each element to ans twice.
Return the concatenated array ans.

Time Complexity:

The time complexity of this approach is O(n), where n is the length of the input array nums.

Space Complexity:

The space complexity of this approach is also O(n), where n is the length of the input array nums.

: :

Solution Code

class Solution {
    public int[] getConcatenation(int[] nums) {
        int n = nums.length;
        int[] ans = new int[2 * n];
        
        for (int i = 0; i < n; i++) {
            ans[i] = nums[i];
            ans[i + n] = nums[i];
        }
        
        return ans;
    }
}

Frequently Asked Questions

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What is the time complexity of LeetCode 1929 (Concatenation of Array)?

The time complexity for LeetCode 1929 (Concatenation of Array) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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1929. Concatenation of Array