LeetCode 1946: Largest Number After Mutating Substring Solution
Master LeetCode problem 1946 (Largest Number After Mutating Substring), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation:
To solve this problem, we can iterate over the characters in the input string num and for each character, we check if changing it to a larger digit using the change array results in a larger number overall. We can achieve this by greedily choosing the maximum digit from change that is larger than the current digit. If we find a larger digit, we update the substring starting from that position and continue the process until we reach the end of the string.
Algorithm:
- Iterate over each character in the input string
num. - For each character, check if changing it to a larger digit using the
changearray results in a larger number overall. - If a larger digit is found, update the substring starting from that position.
- Continue this process until the end of the string is reached.
- Return the modified string as the result.
Time Complexity:
The time complexity of this solution is O(n), where n is the length of the input string num.
Space Complexity:
The space complexity of this solution is O(1) as we are not using any extra space that grows with the input size.
:
Solution Code
class Solution {
public String maximumNumber(String num, int[] change) {
char[] numArray = num.toCharArray();
boolean changed = false;
for (int i = 0; i < numArray.length; i++) {
int digit = numArray[i] - '0';
if (change[digit] > digit) {
changed = true;
numArray[i] = (char)(change[digit] + '0');
} else if (changed && change[digit] < digit) {
break;
}
}
return String.valueOf(numArray);
}
}Try It Yourself
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