LeetCode 1953: Maximum Number of Weeks for Which You Can Work Solution
Master LeetCode problem 1953 (Maximum Number of Weeks for Which You Can Work), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To maximize the number of weeks you can work on the projects, we need to consider the project with the most milestones and ensure we alternate between working on that project and another project to avoid violating the rules. We can calculate the maximum number of weeks by summing all milestones and subtracting the maximum milestone value. If the maximum milestone value is greater than or equal to the sum of all other milestones, we can work on all projects except the one with the maximum milestone value for one extra week.
Solution Code
class Solution {
public long numberOfWeeks(int[] milestones) {
long sum = 0, maxMilestone = 0;
for (int milestone : milestones) {
sum += milestone;
maxMilestone = Math.max(maxMilestone, milestone);
}
return Math.min((sum - maxMilestone) * 2 + 1, sum);
}
}Try It Yourself
Loading code editor...
Related LeetCode Problems
Frequently Asked Questions
How to solve LeetCode 1953 (Maximum Number of Weeks for Which You Can Work)?
This page provides optimized solutions for LeetCode problem 1953 (Maximum Number of Weeks for Which You Can Work) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.
What is the time complexity of LeetCode 1953 (Maximum Number of Weeks for Which You Can Work)?
The time complexity for LeetCode 1953 (Maximum Number of Weeks for Which You Can Work) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
Can I run code for LeetCode 1953 on DevExCode?
Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 1953 in Java, C++, or Python.