LeetCode 1968: Array With Elements Not Equal to Average of Neighbors Solution

Master LeetCode problem 1968 (Array With Elements Not Equal to Average of Neighbors), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1968. Array With Elements Not Equal to Average of Neighbors

Medium

Array Greedy Sorting

Problem Explanation

Explanation:

To solve this problem, we can first sort the input array nums. Then, we can create two new arrays result1 and result2 to store the rearranged elements. We will then iterate through the sorted nums array and distribute the elements alternatively between result1 and result2. Finally, we will merge result1 and result2 to get the final rearranged array.

Algorithm:

Sort the input array nums.
Create two arrays result1 and result2.
Iterate through the sorted nums array and distribute the elements alternatively between result1 and result2.
Merge result1 and result2 to get the final rearranged array.

Time Complexity:

The time complexity of this solution is O(nlogn) due to the sorting step, where n is the number of elements in the input array.

Space Complexity:

The space complexity of this solution is O(n) to store the two result arrays.

Solution Code

class Solution {
    public int[] rearrangeArray(int[] nums) {
        Arrays.sort(nums);
        int n = nums.length;
        int[] result1 = new int[n];
        int[] result2 = new int[n];
        
        int idx = 0;
        for (int i = 0; i < n; i += 2) {
            result1[i] = nums[idx++];
        }
        
        for (int i = 1; i < n; i += 2) {
            result2[i] = nums[idx++];
        }
        
        return mergeArrays(result1, result2);
    }
    
    private int[] mergeArrays(int[] arr1, int[] arr2) {
        int n = arr1.length + arr2.length;
        int[] result = new int[n];
        
        int idx = 0;
        for (int i = 0; i < arr1.length; i++) {
            result[idx] = arr1[i];
            idx++;
        }
        
        for (int i = 0; i < arr2.length; i++) {
            result[idx] = arr2[i];
            idx++;
        }
        
        return result;
    }
}

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