LeetCode 1973: Count Nodes Equal to Sum of Descendants Solution
Master LeetCode problem 1973 (Count Nodes Equal to Sum of Descendants), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1973. Count Nodes Equal to Sum of Descendants
Problem Explanation
Explanation:
To solve this problem, we can perform a Depth First Search (DFS) traversal of the binary tree and at each node, calculate the sum of its descendants. If the sum of the node's descendants is equal to the value of the node itself, we increment a count variable.
Algorithm:
- Implement a recursive function
dfsto perform DFS traversal. - In the
dfsfunction, calculate the sum of the left and right subtrees for each node. - Check if the sum of the left and right subtrees is equal to the value of the current node. If true, increment the count.
- Return the total sum of the left and right subtrees plus the value of the current node.
Time Complexity:
The time complexity of this approach is O(N), where N is the number of nodes in the binary tree.
Space Complexity:
The space complexity of this approach is O(H), where H is the height of the binary tree.
: :
Solution Code
class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) { val = x; }
}
class Solution {
int count = 0;
public int countSum(TreeNode root) {
dfs(root);
return count;
}
private int dfs(TreeNode node) {
if (node == null) {
return 0;
}
int leftSum = dfs(node.left);
int rightSum = dfs(node.right);
if (leftSum + rightSum == node.val) {
count++;
}
return leftSum + rightSum + node.val;
}
}Try It Yourself
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