LeetCode 1980: Find Unique Binary String Solution

Master LeetCode problem 1980 (Find Unique Binary String), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1980. Find Unique Binary String

Medium

Array Hash Table String Backtracking

Problem Explanation

Explanation:

To find a unique binary string of length n that does not appear in the given array of binary strings, we can iterate through all binary strings of length n and check if each string exists in the input array. If a string does not exist in the array, we return it as the answer. This approach ensures that the returned string is unique and not present in the input array.

Algorithm:

Generate all possible binary strings of length n.
Check each generated binary string if it exists in the input array.
Return the first binary string that is not present in the input array.

Time Complexity: O(2^n) where n is the length of the binary strings.
Space Complexity: O(1) as we are not using any extra space other than the input and output.

Solution Code

class Solution {
    public String findDifferentBinaryString(String[] nums) {
        int n = nums.length;
        for (int i = 0; i < (1 << n); i++) {
            String binary = Integer.toBinaryString(i);
            while (binary.length() < n) {
                binary = "0" + binary;
            }
            boolean found = false;
            for (String num : nums) {
                if (num.equals(binary)) {
                    found = true;
                    break;
                }
            }
            if (!found) {
                return binary;
            }
        }
        return "";
    }
}

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