LeetCode 199: Binary Tree Right Side View Solution
Master LeetCode problem 199 (Binary Tree Right Side View), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
199. Binary Tree Right Side View
Problem Explanation
Explanation:
- We can solve this problem using a level order traversal of the binary tree while keeping track of the rightmost node at each level.
- At each level of the tree, the rightmost node will be the last node encountered during the level order traversal.
- We can implement this by using a queue for level order traversal and updating the result array with the rightmost node at each level.
Solution Code
import java.util.*;
class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> result = new ArrayList<>();
if (root == null) {
return result;
}
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
while (!queue.isEmpty()) {
int size = queue.size();
int rightValue = 0;
for (int i = 0; i < size; i++) {
TreeNode node = queue.poll();
rightValue = node.val;
if (node.left != null) {
queue.offer(node.left);
}
if (node.right != null) {
queue.offer(node.right);
}
}
result.add(rightValue);
}
return result;
}
}Try It Yourself
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