LeetCode 2011: Final Value of Variable After Performing Operations Solution

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2011. Final Value of Variable After Performing Operations

Problem Explanation

Explanation:

To solve this problem, we can iterate through the array of operations and update the value of variable X based on the operation. For each operation, we check whether it increments or decrements X, and update X accordingly. Finally, we return the final value of X.

  • Initialize X to 0.
  • Iterate through the operations array.
  • For each operation:
    • If it is "++X" or "X++", increment X by 1.
    • If it is "--X" or "X--", decrement X by 1.
  • Return the final value of X.

Time Complexity:

  • The time complexity of this solution is O(N), where N is the number of operations in the array.

Space Complexity:

  • The space complexity of this solution is O(1) as we are using a constant amount of extra space.

:

Solution Code

class Solution {
    public int finalValueAfterOperations(String[] operations) {
        int X = 0;
        for (String op : operations) {
            if (op.equals("++X") || op.equals("X++")) {
                X++;
            } else {
                X--;
            }
        }
        return X;
    }
}

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