LeetCode 2027: Minimum Moves to Convert String Solution

Master LeetCode problem 2027 (Minimum Moves to Convert String), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2027. Minimum Moves to Convert String

Easy

String Greedy

Problem Explanation

Explanation:

To solve this problem, we need to count the number of 'X' characters in the input string and then calculate the minimum number of moves required to convert all 'X' characters to 'O'.

Initialize a counter to keep track of the number of 'X' characters.
Iterate through the input string and count the number of 'X' characters.
The minimum number of moves required is the total count of 'X' characters divided by 3 (since each move converts 3 consecutive characters to 'O'). :

Solution Code

class Solution {
    public int minimumMoves(String s) {
        int countX = 0;
        for(char c : s.toCharArray()) {
            if(c == 'X') {
                countX++;
            }
        }
        return countX / 3;
    }
}

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