LeetCode 2032: Two Out of Three Solution

Master LeetCode problem 2032 (Two Out of Three), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2032. Two Out of Three

Easy

Array Hash Table Bit Manipulation

Problem Explanation

Explanation:

To solve this problem, we can use a hashmap to keep track of the count of each element across all three arrays. We iterate through each array, updating the count in the hashmap. Finally, we iterate through the hashmap and collect all elements that have a count of at least 2.

Create a hashmap to store the count of elements.
Iterate through each array and update the count in the hashmap.
Iterate through the hashmap and collect elements with a count of at least 2.

Time Complexity: O(n), where n is the total number of elements in all three arrays. Space Complexity: O(n), for the hashmap.

: :

Solution Code

import java.util.*;

class Solution {
    public List<Integer> twoOutOfThree(int[] nums1, int[] nums2, int[] nums3) {
        Map<Integer, Integer> countMap = new HashMap<>();
        
        for (int num : nums1) {
            countMap.put(num, countMap.getOrDefault(num, 0) + 1);
        }
        for (int num : nums2) {
            countMap.put(num, countMap.getOrDefault(num, 0) + 1);
        }
        for (int num : nums3) {
            countMap.put(num, countMap.getOrDefault(num, 0) + 1);
        }
        
        List<Integer> result = new ArrayList<>();
        for (Map.Entry<Integer, Integer> entry : countMap.entrySet()) {
            if (entry.getValue() >= 2) {
                result.add(entry.getKey());
            }
        }
        
        return result;
    }
}

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