LeetCode 2037: Minimum Number of Moves to Seat Everyone Solution

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2037. Minimum Number of Moves to Seat Everyone

Problem Explanation

Explanation:

To solve this problem, we need to minimize the total moves required to seat each student such that no two students are in the same seat. We can achieve this by sorting the arrays seats and students, then calculating the total moves needed based on the distance between the positions in the sorted arrays.

  1. Sort the seats and students arrays.
  2. Initialize a variable totalMoves to 0.
  3. Iterate over each student and calculate the absolute difference between the corresponding seat position and the student position.
  4. Add this difference to totalMoves.
  5. Return totalMoves. :

Solution Code

import java.util.Arrays;

class Solution {
    public int minMovesToSeat(int[] seats, int[] students) {
        Arrays.sort(seats);
        Arrays.sort(students);

        int totalMoves = 0;
        for (int i = 0; i < seats.length; i++) {
            totalMoves += Math.abs(seats[i] - students[i]);
        }

        return totalMoves;
    }
}

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