LeetCode 2048: Next Greater Numerically Balanced Number Solution

Master LeetCode problem 2048 (Next Greater Numerically Balanced Number), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2048. Next Greater Numerically Balanced Number

Medium

Hash Table Math Backtracking Counting Enumeration

Problem Explanation

Explanation:

To find the smallest numerically balanced number strictly greater than n, we can start by incrementing n until we find a numerically balanced number. To check if a number is numerically balanced, we can count the occurrences of each digit in the number and compare it with the digit itself. If all digits satisfy this condition, we have found a numerically balanced number.

Solution Code

class Solution {
    public int nextNumericallyBalancedNumber(int n) {
        while (true) {
            n++;
            if (isNumericallyBalanced(n)) {
                return n;
            }
        }
    }
    
    private boolean isNumericallyBalanced(int num) {
        String numStr = String.valueOf(num);
        int[] count = new int[10];
        
        for (char c : numStr.toCharArray()) {
            count[c - '0']++;
        }
        
        for (int i = 0; i < numStr.length(); i++) {
            if (count[numStr.charAt(i) - '0'] != numStr.charAt(i) - '0') {
                return false;
            }
        }
        
        return true;
    }
}

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