LeetCode 2057: Smallest Index With Equal Value Solution

Master LeetCode problem 2057 (Smallest Index With Equal Value), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2057. Smallest Index With Equal Value

Easy

Array

Problem Explanation

Explanation

To solve this problem, we can iterate through the given array and check if the current index i satisfies the condition i mod 10 == nums[i]. If we find such an index, we return it as the smallest index that meets the condition. If no index satisfies the condition, we return -1.

Start iterating through the array.
For each index i, check if i mod 10 == nums[i].
If the condition is met, return the current index i.
If no index satisfies the condition, return -1.

Time Complexity: O(N) where N is the number of elements in the input array nums. Space Complexity: O(1)

Solution Code

class Solution {
    public int smallestIndexEqualValue(int[] nums) {
        for (int i = 0; i < nums.length; i++) {
            if (i % 10 == nums[i]) {
                return i;
            }
        }
        return -1;
    }
}

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What is the time complexity of LeetCode 2057 (Smallest Index With Equal Value)?

The time complexity for LeetCode 2057 (Smallest Index With Equal Value) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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