LeetCode 2058: Find the Minimum and Maximum Number of Nodes Between Critical Points Solution

Master LeetCode problem 2058 (Find the Minimum and Maximum Number of Nodes Between Critical Points), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2058. Find the Minimum and Maximum Number of Nodes Between Critical Points

Medium

Linked List

Problem Explanation

Explanation

To solve this problem, we iterate through the linked list and identify the critical points (local minima and local maxima). We keep track of the indices of these critical points and calculate the distances between them. Finally, we find the minimum and maximum distances between any two distinct critical points.

We iterate through the linked list to identify local minima and maxima.
Keep track of the indices of these critical points.
Calculate the distances between the critical points.
Find the minimum and maximum distances between any two distinct critical points.

Time Complexity: O(N) where N is the number of nodes in the linked list. Space Complexity: O(1)

Solution Code

class ListNode {
    int val;
    ListNode next;

    ListNode(int val) {
        this.val = val;
    }
}

class Solution {
    public int[] findCriticalPoints(ListNode head) {
        if (head == null || head.next == null) {
            return new int[]{-1, -1};
        }

        ListNode curr = head;
        int minDistance = Integer.MAX_VALUE;
        int maxDistance = Integer.MIN_VALUE;
        int prev = -1;
        int idx = 0;

        while (curr.next != null) {
            if ((prev != -1 && curr.val < prev && curr.val < curr.next.val) ||
                (prev != -1 && curr.val > prev && curr.val > curr.next.val)) {
                if (prev != -1) {
                    minDistance = Math.min(minDistance, idx - prev);
                    maxDistance = Math.max(maxDistance, idx - prev);
                }
                prev = idx;
            }
            idx++;
            curr = curr.next;
        }

        return minDistance == Integer.MAX_VALUE ? new int[]{-1, -1} : new int[]{minDistance, maxDistance};
    }
}

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