LeetCode 2059: Minimum Operations to Convert Number Solution

Master LeetCode problem 2059 (Minimum Operations to Convert Number), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2059. Minimum Operations to Convert Number

Medium

Array Breadth-First Search

Problem Explanation

Explanation

To solve this problem, we can use a breadth-first search (BFS) approach. We start with the start value and explore all possible operations using the numbers in the nums array. We keep track of the number of operations needed to reach each possible value of x using a map. We continue exploring until we find the goal value or until we exhaust all possibilities.

Algorithm:

Initialize a map to store the minimum operations needed to reach each value of x.
Initialize a queue for BFS and add the start value to the queue with 0 operations.
Perform BFS by popping values from the queue and exploring all possible operations using the numbers in the nums array.
Update the minimum operations needed to reach each new value of x in the map.
Continue until we find the goal value or exhaust all possibilities.
Return the minimum operations needed to reach goal from start.

Time Complexity:

The time complexity of this approach is O(N * M), where N is the number of elements in the nums array and M is the maximum possible value of x (1000 in this case).

Space Complexity:

The space complexity is O(M) to store the minimum operations for each possible value of x.

Solution Code

import java.util.*;

class Solution {
    public int minOperations(int[] nums, int start, int goal) {
        Map<Integer, Integer> operations = new HashMap<>();
        Queue<Integer> queue = new LinkedList<>();
        
        operations.put(start, 0);
        queue.offer(start);
        
        while (!queue.isEmpty()) {
            int curr = queue.poll();
            int ops = operations.get(curr);
            
            if (curr == goal) {
                return ops;
            }
            
            for (int num : nums) {
                int next1 = curr + num;
                int next2 = curr - num;
                int next3 = curr ^ num;
                
                if (!operations.containsKey(next1)) {
                    operations.put(next1, ops + 1);
                    queue.offer(next1);
                }
                if (!operations.containsKey(next2)) {
                    operations.put(next2, ops + 1);
                    queue.offer(next2);
                }
                if (!operations.containsKey(next3)) {
                    operations.put(next3, ops + 1);
                    queue.offer(next3);
                }
            }
        }
        
        return -1;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 2059 (Minimum Operations to Convert Number)?

This page provides optimized solutions for LeetCode problem 2059 (Minimum Operations to Convert Number) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2059 (Minimum Operations to Convert Number)?

The time complexity for LeetCode 2059 (Minimum Operations to Convert Number) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2059 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2059 in Java, C++, or Python.

Back to LeetCode Solutions