LeetCode 2070: Most Beautiful Item for Each Query Solution

Master LeetCode problem 2070 (Most Beautiful Item for Each Query), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2070. Most Beautiful Item for Each Query

Medium

Array Binary Search Sorting

Problem Explanation

Explanation

To solve this problem, we can first sort the items based on their prices. Then, for each query, we can iterate through the sorted items to find the item with the maximum beauty whose price is less than or equal to the query. We can use a binary search to efficiently find the correct item.

Solution Code

import java.util.Arrays;

class Solution {
    public int[] maxBeauty(int[][] items, int[] queries) {
        Arrays.sort(items, (a, b) -> a[0] - b[0]);
        int[] result = new int[queries.length];

        for (int i = 0; i < queries.length; i++) {
            int query = queries[i];
            int maxBeauty = 0;

            for (int j = items.length - 1; j >= 0; j--) {
                if (items[j][0] <= query) {
                    maxBeauty = Math.max(maxBeauty, items[j][1]);
                } else {
                    break;
                }
            }

            result[i] = maxBeauty;
        }

        return result;
    }
}

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