LeetCode 2073: Time Needed to Buy Tickets Solution

Master LeetCode problem 2073 (Time Needed to Buy Tickets), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2073. Time Needed to Buy Tickets

Easy

Array Queue Simulation

Problem Explanation

Explanation

To solve this problem, we can simulate the process of people buying tickets in a queue. We iterate through the queue, decrementing the number of tickets each person wants to buy and moving them to the end of the queue if they still have tickets left. We keep track of the time taken until the person at position k has bought all their tickets.

Algorithm:

Initialize a queue to represent the line of people.
Iterate through the queue:
- Decrement the number of tickets the person wants to buy.
- If the person still has tickets left, move them to the end of the queue.
- Increment the time taken.
- If the person at position k has bought all their tickets, return the time taken.

Time Complexity:

The time complexity of this algorithm is O(n * max(tickets)), where n is the number of people in the queue and max(tickets) is the maximum number of tickets any person wants to buy.

Space Complexity:

The space complexity of this algorithm is O(n) to store the queue of people.

Solution Code

class Solution {
    public int buyTicketTime(int[] tickets, int k) {
        Queue<Integer> queue = new LinkedList<>();
        for (int i = 0; i < tickets.length; i++) {
            queue.add(tickets[i]);
        }

        int time = 0;
        while (!queue.isEmpty()) {
            int front = queue.poll();
            time++;
            if (front > 1) {
                queue.add(front - 1);
            }
            if (k == 0) {
                if (front == 1) {
                    return time;
                }
            } else {
                k = (k + queue.size()) % queue.size();
            }
        }

        return time;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 2073 (Time Needed to Buy Tickets)?

This page provides optimized solutions for LeetCode problem 2073 (Time Needed to Buy Tickets) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2073 (Time Needed to Buy Tickets)?

The time complexity for LeetCode 2073 (Time Needed to Buy Tickets) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2073 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2073 in Java, C++, or Python.

Back to LeetCode Solutions