LeetCode 2082: The Number of Rich Customers Solution

Master LeetCode problem 2082 (The Number of Rich Customers), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2082. The Number of Rich Customers

Easy

Database

Problem Explanation

Explanation:

To solve this problem, we need to iterate through each customer and check if their wealth is greater than or equal to a given threshold. We will keep a count of the rich customers and return this count at the end.

Initialize a variable richCount to 0.
Iterate through each customer's wealth.
If the wealth of the customer is greater than or equal to the threshold, increment the richCount.
Finally, return the richCount.

Time Complexity:

The time complexity of this solution is O(N), where N is the number of customers.

Space Complexity:

The space complexity of this solution is O(1) as we are using a constant amount of extra space.

: :

Solution Code

class Solution {
    public int numRichCustomers(int[][] accounts, int threshold) {
        int richCount = 0;
        for (int i = 0; i < accounts.length; i++) {
            int wealth = 0;
            for (int j = 0; j < accounts[i].length; j++) {
                wealth += accounts[i][j];
            }
            if (wealth >= threshold) {
                richCount++;
            }
        }
        return richCount;
    }
}

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