LeetCode 2089: Find Target Indices After Sorting Array Solution
Master LeetCode problem 2089 (Find Target Indices After Sorting Array), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2089. Find Target Indices After Sorting Array
Problem Explanation
Explanation
To solve this problem, we can first create a mapping of each element to its original index in the input array. Then, we sort the array in non-decreasing order. After sorting, we iterate through the sorted array and check if the element is equal to the target. If it is, we add the original index of that element to the result list. Finally, we return the result list sorted in increasing order.
- Time complexity: O(n log n) where n is the number of elements in the array due to sorting.
- Space complexity: O(n) to store the mapping of each element to its index.
Solution Code
import java.util.*;
class Solution {
public List<Integer> findTargetIndices(int[] nums, int target) {
List<Integer> result = new ArrayList<>();
Map<Integer, Integer> indexMap = new HashMap<>();
for (int i = 0; i < nums.length; i++) {
indexMap.put(nums[i], i);
}
Arrays.sort(nums);
for (int i = 0; i < nums.length; i++) {
if (nums[i] == target) {
result.add(indexMap.get(target));
}
}
Collections.sort(result);
return result;
}
}Try It Yourself
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