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LeetCode 2092: Find All People With Secret Solution

Master LeetCode problem 2092 (Find All People With Secret), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

Problem Explanation

Explanation:

  • We can solve this problem using a breadth-first search (BFS) approach.
  • We need to maintain a queue of people who know the secret and a set to keep track of people who already know the secret.
  • We start with the first person who knows the secret and add them to the queue and set.
  • We iterate through the meetings, each time updating the queue with the new people who know the secret and adding them to the set.
  • We continue this process until there are no more new people to add to the queue.
  • Finally, we return the set of people who know the secret.

Time Complexity: O(N + E), where N is the number of people and E is the number of meetings.

Space Complexity: O(N) for the set and queue.

:

Solution Code

import java.util.*;

class Solution {
    public List<Integer> findSecret(int n, int[][] meetings, int firstPerson) {
        List<Integer> result = new ArrayList<>();
        Set<Integer> knowSecret = new HashSet<>();
        Queue<Integer> queue = new LinkedList<>();

        knowSecret.add(firstPerson);
        queue.offer(firstPerson);

        while (!queue.isEmpty()) {
            int currPerson = queue.poll();
            for (int[] meeting : meetings) {
                if (meeting[0] == currPerson && !knowSecret.contains(meeting[1])) {
                    knowSecret.add(meeting[1]);
                    queue.offer(meeting[1]);
                } else if (meeting[1] == currPerson && !knowSecret.contains(meeting[0])) {
                    knowSecret.add(meeting[0]);
                    queue.offer(meeting[0]);
                }
            }
        }

        result.addAll(knowSecret);
        return result;
    }
}

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