LeetCode 2098: Subsequence of Size K With the Largest Even Sum Solution
Master LeetCode problem 2098 (Subsequence of Size K With the Largest Even Sum), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To solve this problem, we can use a recursive approach to generate all possible subsequences of size k. For each subsequence, we calculate the sum and check if it is even and larger than the current maximum even sum. If so, we update the maximum even sum.
Algorithm:
- Define a recursive function to generate all subsequences of size
k. - For each subsequence, calculate the sum and check if it is even and larger than the current maximum even sum.
- Update the maximum even sum if necessary.
- Return the maximum even sum found.
Time Complexity:
- The time complexity of the recursive approach is O(2^N) where N is the length of the input array.
Space Complexity:
- The space complexity of the recursive approach is O(N) for the call stack.
Solution Code
class Solution {
int maxEvenSum = Integer.MIN_VALUE;
public int maxEvenSum(int[] nums, int k) {
generateSubsequences(nums, k, 0, 0);
return maxEvenSum;
}
private void generateSubsequences(int[] nums, int k, int index, int sum) {
if (k == 0) {
if (sum % 2 == 0 && sum > maxEvenSum) {
maxEvenSum = sum;
}
return;
}
for (int i = index; i < nums.length; i++) {
generateSubsequences(nums, k - 1, i + 1, sum + nums[i]);
}
}
}Try It Yourself
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What is the time complexity of LeetCode 2098 (Subsequence of Size K With the Largest Even Sum)?
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