LeetCode 2101: Detonate the Maximum Bombs Solution
Master LeetCode problem 2101 (Detonate the Maximum Bombs), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2101. Detonate the Maximum Bombs
Problem Explanation
Explanation:
To solve this problem, we can iterate through each bomb and simulate the detonation process for each bomb. For each bomb, we calculate the number of bombs that will be detonated if that bomb is detonated. We keep track of the maximum number of bombs detonated by any single bomb and return that as the final answer.
Here is the step-by-step algorithm:
- Initialize a variable
maxDetonatedto 0. - Iterate through each bomb in the input array.
- For each bomb, calculate the number of bombs that will be detonated if that bomb is detonated.
- Update
maxDetonatedif the number of detonated bombs for the current bomb is greater. - Return
maxDetonatedas the final answer.
The time complexity of this algorithm is O(n^2) where n is the number of bombs since for each bomb, we potentially iterate through all other bombs. The space complexity is O(1) since we are not using any extra space.
Solution Code
class Solution {
public int maxDetonatedBombs(int[][] bombs) {
int maxDetonated = 0;
for (int i = 0; i < bombs.length; i++) {
int detonated = 1;
for (int j = 0; j < bombs.length; j++) {
if (j != i) {
int distance = (bombs[i][0] - bombs[j][0]) * (bombs[i][0] - bombs[j][0]) +
(bombs[i][1] - bombs[j][1]) * (bombs[i][1] - bombs[j][1]);
int range = (bombs[i][2] + bombs[j][2]) * (bombs[i][2] + bombs[j][2]);
if (distance <= range) {
detonated++;
}
}
}
maxDetonated = Math.max(maxDetonated, detonated);
}
return maxDetonated;
}
}Try It Yourself
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