LeetCode 2102: Sequentially Ordinal Rank Tracker Solution

Master LeetCode problem 2102 (Sequentially Ordinal Rank Tracker), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2102. Sequentially Ordinal Rank Tracker

Hard

Design Heap (Priority Queue)Data Stream Ordered Set

Problem Explanation

Explanation

To solve this problem, we can maintain a priority queue (min-heap) to store the locations based on their scores and names. We will also keep track of the number of queries made so far. When a new location is added, we insert it into the priority queue. When a query is made, we pop elements from the priority queue until we reach the ith best location.

Algorithm:

Initialize a priority queue to store locations based on their scores and names.
Initialize a variable to keep track of the number of queries made.
Implement the SORTracker class with methods:
- SORTracker(): Initializes the tracker system.
- add(String name, int score): Adds a scenic location with name and score to the system.
- get(): Queries and returns the ith best location based on the number of times this method has been invoked.
When adding a location, create a custom Location class to store the name and score of each location.
When querying, pop elements from the priority queue until the ith best location is reached.

Time Complexity:

Adding a location: O(log n) where n is the number of locations added.
Querying: O(i) where i is the number of times get() is called.

Space Complexity:

O(n) where n is the total number of locations added.

Solution Code

import java.util.PriorityQueue;

class SORTracker {
    private class Location implements Comparable<Location> {
        String name;
        int score;

        public Location(String name, int score) {
            this.name = name;
            this.score = score;
        }

        @Override
        public int compareTo(Location other) {
            if (this.score == other.score) {
                return this.name.compareTo(other.name);
            }
            return Integer.compare(other.score, this.score);
        }
    }

    private PriorityQueue<Location> locations;
    private int queries;

    public SORTracker() {
        locations = new PriorityQueue<>();
        queries = 0;
    }

    public void add(String name, int score) {
        locations.add(new Location(name, score));
    }

    public String get() {
        queries++;
        PriorityQueue<Location> copy = new PriorityQueue<>(locations);
        while (queries > 1) {
            copy.poll();
            queries--;
        }
        return copy.peek().name;
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 2102 (Sequentially Ordinal Rank Tracker)?

This page provides optimized solutions for LeetCode problem 2102 (Sequentially Ordinal Rank Tracker) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 2102 (Sequentially Ordinal Rank Tracker)?

The time complexity for LeetCode 2102 (Sequentially Ordinal Rank Tracker) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 2102 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 2102 in Java, C++, or Python.

Back to LeetCode Solutions