LeetCode 2103: Rings and Rods Solution
Master LeetCode problem 2103 (Rings and Rods), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
2103. Rings and Rods
Problem Explanation
Explanation:
To solve this problem, we need to iterate through the given rings and count the number of rods that have all three colors of rings on them. We can use a HashMap to keep track of the distinct colors on each rod. We iterate through the rings in pairs and update the HashMap accordingly. Finally, we count the number of rods that have all three colors.
- Create a HashMap to store the colors on each rod.
- Iterate through the rings in pairs.
- Update the HashMap with the colors on each rod.
- Count the number of rods that have all three colors.
Time Complexity: O(n) Space Complexity: O(1)
:
Solution Code
class Solution {
public int countRodsWithAllColors(String rings) {
int n = rings.length() / 2;
Map<Character, Set<Character>> rodsColors = new HashMap<>();
for (int i = 0; i < n; i++) {
char color = rings.charAt(2 * i);
char rod = rings.charAt(2 * i + 1);
rodsColors.putIfAbsent(rod, new HashSet<>());
rodsColors.get(rod).add(color);
}
int count = 0;
for (Set<Character> colors : rodsColors.values()) {
if (colors.size() == 3) {
count++;
}
}
return count;
}
}Try It Yourself
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