LeetCode 2110: Number of Smooth Descent Periods of a Stock Solution

Master LeetCode problem 2110 (Number of Smooth Descent Periods of a Stock), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

2110. Number of Smooth Descent Periods of a Stock

Medium

Array Math Dynamic Programming

Problem Explanation

Explanation

To solve this problem, we can iterate through the given array of stock prices and count the number of smooth descent periods. For each element in the array, we check if it is smaller than the previous element by exactly 1. If it is, then we have found a smooth descent period. We increment the count and continue checking for more smooth descent periods.

Algorithm

Initialize a variable count to 0 to keep track of the number of smooth descent periods.
Iterate through the array of prices starting from index 1.
Check if the current price is exactly 1 less than the previous price.
If the condition is met, increment the count.
Continue iterating until the end of the array.
Return the final count as the result.

Time Complexity

The time complexity of this algorithm is O(n), where n is the number of elements in the input array.

Space Complexity

The space complexity of this algorithm is O(1) as we are not using any extra space proportional to the input size.

Solution Code

class Solution {
    public int countSmoothDescentPeriods(int[] prices) {
        int count = 0;
        
        for (int i = 1; i < prices.length; i++) {
            if (prices[i] == prices[i - 1] - 1) {
                count++;
            }
        }
        
        return count;
    }
}

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What is the time complexity of LeetCode 2110 (Number of Smooth Descent Periods of a Stock)?

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